20q+q^2=800

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Solution for 20q+q^2=800 equation:


Simplifying
20q + q2 = 800

Solving
20q + q2 = 800

Solving for variable 'q'.

Reorder the terms:
-800 + 20q + q2 = 800 + -800

Combine like terms: 800 + -800 = 0
-800 + 20q + q2 = 0

Factor a trinomial.
(-40 + -1q)(20 + -1q) = 0

Subproblem 1

Set the factor '(-40 + -1q)' equal to zero and attempt to solve: Simplifying -40 + -1q = 0 Solving -40 + -1q = 0 Move all terms containing q to the left, all other terms to the right. Add '40' to each side of the equation. -40 + 40 + -1q = 0 + 40 Combine like terms: -40 + 40 = 0 0 + -1q = 0 + 40 -1q = 0 + 40 Combine like terms: 0 + 40 = 40 -1q = 40 Divide each side by '-1'. q = -40 Simplifying q = -40

Subproblem 2

Set the factor '(20 + -1q)' equal to zero and attempt to solve: Simplifying 20 + -1q = 0 Solving 20 + -1q = 0 Move all terms containing q to the left, all other terms to the right. Add '-20' to each side of the equation. 20 + -20 + -1q = 0 + -20 Combine like terms: 20 + -20 = 0 0 + -1q = 0 + -20 -1q = 0 + -20 Combine like terms: 0 + -20 = -20 -1q = -20 Divide each side by '-1'. q = 20 Simplifying q = 20

Solution

q = {-40, 20}

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